Question

0.24g of a volatile substance,upon vaporisation,gives 45ml vapour at NTP what will be the vapour density of the substance?

Answer 1

So this gas has a mass of 0.24g and a volume at NTP of 45 mL. What is the mass of H2 at NTP of 45 mL.
n of H2 = 0.045L/molar volume @ NTP = ?
Solve for n of H2.
Then n x molar mass H2 = grams.
v.d. = mass unknown gas/g H2 for that volume.

Answer 2

vapour density=vapour of gas/vapour of H2
vapour density =mass of 1L of vapour/mass of 1L of H2
massof 1L vapour= 0.24* 1000 kg
mass of 1L of H2 =vol*density =4580.089 kg
vapour density = 0.24*1000 /45*0.089=59.93

Answer 3

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Answer 4

First find the molar mass of the substance at NTP
Mass= 22400×0.24/45
=119.46
Density=M mass/2
=119.46/2
= 59.73
Answer= 59.73

Answer 5

Use ideal gas equations St NTP to find molar mass
PV=nRT