Question
The average kinetic energy of an ideal gas,per molecule in S.I units at 25°C will be
Answers
Anonymous
Average kinetic energy = (3/2)KT
=3/2 kT
=3/2 ×8.314/6.022×(10)^(-23) ×298
=6.17×(10)^(-21)
=3/2 kT
=3/2 ×8.314/6.022×(10)^(-23) ×298
=6.17×(10)^(-21)