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P1V1 = P2V2
At 25°C and 730 mm pressure,380 ml of dry oxygen was collected.If the temperature is constant ,what volume will the oxygen occupy at 760 mm pressure ?
ANSWER- 365ml
6 answers
p1v1=p2v2
730*380/760=v2
365ml
730*380/760=v2
365ml
P1v1= p2v2 730×380=760× v2 277400=760v2 v2 =277400/760=365 ml
P1v1=p2v2
730*380 = 760*v2
V2=365ml
730*380 = 760*v2
V2=365ml
730*380/760=365
At hundred degree Celsius and 1 ATM pressure if the density of liquid water is 1 gram per cm cube and that of water vapour is 0.0006 gram per centimetre cube the volume occupied by the water molecule in 1 litre of steam at the temperature is