Asked by Anonymous

a car goes over a circular hill of 50m radius at a constant speed of 20m/sec . What is the force of the car on the 600N driver at the top of the hill.?

10 years ago

Answered by Anonymous

what is 600N-600/g*20^2/50 ?

mg-mv^2/r

10 years ago

Answered by Anonymous

Yeah I got 600- 61.2(40)/50 =551.64. I do not know if that is right .

10 years ago

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