Asked by JAMES
A silver cube (density of silver is 10 g/cm3) with side length of 3 cm weighs more than an aluminium cube (density of aluminium is 2.96 g/cm3) with side length of 4 cm. The cubes are each suspended by a string and allowed to be completely immersed in two identical jars containing the same amount of water (see figure below). If the strings of both objects were cut and they sink to the bottom of the containers, which weighing scale will show a bigger reading now?
Answers
Answered by
Henry
Silver:
V = L*W*h = 3*3*3 = 3^3 = 27 cm^3
Wt. = V*D = 27cm^3 * 10g/cm^3=270 grams
Aluminum:
V = 4*4*4 = 64 cm^3
Wt. = 64cm^3 * 2.96g/cm^3 = 189.4 grams
V = L*W*h = 3*3*3 = 3^3 = 27 cm^3
Wt. = V*D = 27cm^3 * 10g/cm^3=270 grams
Aluminum:
V = 4*4*4 = 64 cm^3
Wt. = 64cm^3 * 2.96g/cm^3 = 189.4 grams
Answered by
Nelson
A silver cube (density of silver is 10 g/cm3) with side length of 3 cm weighs more than an aluminium cube (density of aluminium is 2.96 g/cm3) with side length of 4 cm.The cubes are each suspended by a string and allowed to be completely immersed in two identical jars containing the same amount of water (see figure below). 1)If the strings of both objects were cut and they sink to the bottom of the containers,which weighing scale will show a bigger reading now?
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