Asked by Irina
The quantity Q of radioactive carbon remaining in a 300 - gram wood sample at time t is given by the expression
Q(t) = 300 e^{- 0.000324*t}.
How much radioactive carbon remains in the sample after
(a) 200 years, (b) 50000 years, (c) 125500 years?
Q(t) = 300 e^{- 0.000324*t}.
How much radioactive carbon remains in the sample after
(a) 200 years, (b) 50000 years, (c) 125500 years?
Answers
Answered by
Steve
what's the trouble? Just plug in the values for t.
For example,
Q(800) = 300 e^(-0.000324*800) = 231.5006
For example,
Q(800) = 300 e^(-0.000324*800) = 231.5006
Answered by
Irina
i just did it
Q(200) = 300 e^(-0.000324*200) = 281.176
But for b) and c) web work doesn't accept my answers
Q(50000) = 300 e^(-0.000324*50000) = 0.000028
maybe i should multiply by something...
Q(200) = 300 e^(-0.000324*200) = 281.176
But for b) and c) web work doesn't accept my answers
Q(50000) = 300 e^(-0.000324*50000) = 0.000028
maybe i should multiply by something...
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