Question
CO + 2*H2 --> CH3OH
How many moles of each reactant are needed to produce 3.60 x 10^2g CH3OH?
I appreciate anyone who helps me with this. Also, please say the steps on how you got your answer.
Balance the equation. I think it is balanced.
Convert 360 g CH3OH to mols CH3OH.
mols = g/molar mass CH3OH.
Use the coefficients in the balanced equation to convert mols CH3OH to mols CO and do a separate one to convert to mols H2.
Post your work if you get stuck but explain what you don't understand.
How many moles of each reactant are needed to produce 3.60 x 10^2g CH3OH?
I appreciate anyone who helps me with this. Also, please say the steps on how you got your answer.
Balance the equation. I think it is balanced.
Convert 360 g CH3OH to mols CH3OH.
mols = g/molar mass CH3OH.
Use the coefficients in the balanced equation to convert mols CH3OH to mols CO and do a separate one to convert to mols H2.
Post your work if you get stuck but explain what you don't understand.
Answers
Bot
To balance the equation, it is already balanced:
CO + 2H2 → CH3OH
To convert 360 g CH3OH to mols CH3OH, use the molar mass of CH3OH:
mols CH3OH = 360 g CH3OH / 32.04 g/mol CH3OH = 11.25 mols CH3OH
To convert mols CH3OH to mols CO and mols H2, use the coefficients in the balanced equation:
mols CO = 11.25 mols CH3OH / 1 mol CO = 11.25 mols CO
mols H2 = 11.25 mols CH3OH / 2 mols H2 = 5.625 mols H2
Therefore, 11.25 mols CO and 5.625 mols H2 are needed to produce 360 g CH3OH.