Asked by katelyn
The difference between 2 positive numbers, x and y where x > y, is 7 and the sum of their squares is 137. By forming 2 equations in x and y, find the product of these 2 numbers.
Answers
Answered by
MathMate
We are given
x²+y²=137
(x-y)=7
this means
49=(x-y)²
=x²-2xy+y²
=x²+y²-2xy
=137-2xy
From
49=137-2xy
can you solve for xy?
The longer way:
equation 1:
x-y=7
equation 2:
x²+y²=137
Now solve the non-linear system in x and y.
x²+y²=137
(x-y)=7
this means
49=(x-y)²
=x²-2xy+y²
=x²+y²-2xy
=137-2xy
From
49=137-2xy
can you solve for xy?
The longer way:
equation 1:
x-y=7
equation 2:
x²+y²=137
Now solve the non-linear system in x and y.
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