Asked by RVE

FUNCTIONS OF A STANDARD NORMAL

The random variable X has a standard normal distribution. Find the PDF of the random variable Y, where:

1. Y=3X-1 , Y = 3X - 1

answer:

fY(y)=1/3*fX*(y+1/3)

f_ Y(y)=1/3*f_ X*(y+1/3)

2. Y=3X^2-1. For y>=-1,
Y = 3X^2 - 1. For y >= -1,

answer:

fY(y)=1/3*sqrt(3/y+1)*fX*sqrt(y+1/3)
f_Y(y)=1/3*sqrt(3/y+1)*f_X*sqrt(y+1/3)

(no need to answer. Public interest problem)

Answers

Answered by JAV
can you give me your email address?
Answered by RVE
could you help me out with some of the other answers???
Answered by JAV
can you post problem set of Week 6?
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