Asked by Ciaria
The velocity of sound in air is given by the equation  , where v is the velocity in meters per second and t is the temperature in degrees Celsius. Find the temperature when the velocity is 329 meters per second by graphing the equation. Round the answer to the nearest degree. show your work
Answers
Answered by
Lily
v=20√(273+t)
329 = 20*sqrt(273+t)
16.45 = sqrt(273+t)
273+t = 16.45^2
t- 16.45^2-273
t = -2.4 degrees celsius
Hope that helps? :)
329 = 20*sqrt(273+t)
16.45 = sqrt(273+t)
273+t = 16.45^2
t- 16.45^2-273
t = -2.4 degrees celsius
Hope that helps? :)
Answered by
Ciaria
Thanks , My answer was -2 , I guess I was close :)
Answered by
Lily
Yes you were! Good job! Glad I could help. :)
Answered by
Anonymous
v=20√(273+t)
329 = 20*sqrt(273+t)
16.45 = sqrt(273+t)
273+t = 16.45^2
t- 16.45^2-273
t = -2.4 degrees celsius
329 = 20*sqrt(273+t)
16.45 = sqrt(273+t)
273+t = 16.45^2
t- 16.45^2-273
t = -2.4 degrees celsius