Asked by Ciaria
                The velocity of sound in air is given by the equation  , where v is the velocity in meters per second and t is the temperature in degrees Celsius. Find the temperature when the velocity is 329 meters per second by graphing the equation. Round the answer to the nearest degree.   show your work 
            
            
        Answers
                    Answered by
            Lily
            
    v=20√(273+t)
329 = 20*sqrt(273+t)
16.45 = sqrt(273+t)
273+t = 16.45^2
t- 16.45^2-273
t = -2.4 degrees celsius
Hope that helps? :)
    
329 = 20*sqrt(273+t)
16.45 = sqrt(273+t)
273+t = 16.45^2
t- 16.45^2-273
t = -2.4 degrees celsius
Hope that helps? :)
                    Answered by
            Ciaria
            
    Thanks , My answer was -2 , I guess I was close :)
    
                    Answered by
            Lily
            
    Yes you were! Good job! Glad I could help. :)
    
                    Answered by
            Anonymous
            
    v=20√(273+t)
329 = 20*sqrt(273+t)
16.45 = sqrt(273+t)
 
273+t = 16.45^2
t- 16.45^2-273
t = -2.4 degrees celsius
    
329 = 20*sqrt(273+t)
16.45 = sqrt(273+t)
273+t = 16.45^2
t- 16.45^2-273
t = -2.4 degrees celsius
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