Asked by Gloria
Solve the following inequalities.
1.) 3x + 2y < 6
2.) 2x^2 + y ≥ 2
1.) 3x + 2y < 6
2.) 2x^2 + y ≥ 2
Answers
Answered by
Gloria
I think for the first one the answer is 2 but the second one I'm not sure about?
Answered by
Steve
the answer to the first one is not 2. What does that even mean?
3x + 2y < 6 means that
2y < 6-3x
y < 3 - 3/2 x
o, you graph the line y = 3 - 3/2 x and everything below that line is where y < 3 - 3/2 x. It's a region, not a number.
2x^2 + y > 2
y > 2 - 2x^2
So, everywhere above the parabola is the solution. See
http://www.wolframalpha.com/input/?i=y+%3E+2+-+2x%5E2
3x + 2y < 6 means that
2y < 6-3x
y < 3 - 3/2 x
o, you graph the line y = 3 - 3/2 x and everything below that line is where y < 3 - 3/2 x. It's a region, not a number.
2x^2 + y > 2
y > 2 - 2x^2
So, everywhere above the parabola is the solution. See
http://www.wolframalpha.com/input/?i=y+%3E+2+-+2x%5E2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.