Solve the following inequalities.
1.) 3x + 2y < 6
2.) 2x^2 + y ≥ 2
2 answers
I think for the first one the answer is 2 but the second one I'm not sure about?
the answer to the first one is not 2. What does that even mean?
3x + 2y < 6 means that
2y < 6-3x
y < 3 - 3/2 x
o, you graph the line y = 3 - 3/2 x and everything below that line is where y < 3 - 3/2 x. It's a region, not a number.
2x^2 + y > 2
y > 2 - 2x^2
So, everywhere above the parabola is the solution. See
http://www.wolframalpha.com/input/?i=y+%3E+2+-+2x%5E2
3x + 2y < 6 means that
2y < 6-3x
y < 3 - 3/2 x
o, you graph the line y = 3 - 3/2 x and everything below that line is where y < 3 - 3/2 x. It's a region, not a number.
2x^2 + y > 2
y > 2 - 2x^2
So, everywhere above the parabola is the solution. See
http://www.wolframalpha.com/input/?i=y+%3E+2+-+2x%5E2
1 answer