Asked by kudu
Kibet left school by bicycle at 8:00 a.m. and took 1 ½ hours to reach the market 20 km away. Akinyi left the school for the market by car at 8:30 a.m. The average speed of the car was 80 km /h. What was the difference between their arrival times?
Answers
Answered by
Henry
Ta = 8:00AM + 1 1/2h = 9:30 AM. = Time
arrived.
d = r*T = 20 km
T = 20/r = 20/80 = 1/4 h. = 15 min. Travel time.
Ta = 8:30AM + 15 min = 8:45 AM. = Time
arrived.
9:30AM - 8:45AM = 8:90 - 8:45 = :45 Min
= Difference in arrival time.
arrived.
d = r*T = 20 km
T = 20/r = 20/80 = 1/4 h. = 15 min. Travel time.
Ta = 8:30AM + 15 min = 8:45 AM. = Time
arrived.
9:30AM - 8:45AM = 8:90 - 8:45 = :45 Min
= Difference in arrival time.
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