Asked by DF
z1=[cos pi/4 +sin pi/4] z2= [cos 2pi+sin 2pi]
z1= sqrt 5 solve.
how do you do this? substitute z1 and do what?
z1= sqrt 5 solve.
how do you do this? substitute z1 and do what?
Answers
Answered by
Steve
actually, z1 = cos pi/4 +sin pi/4 i
that is (1,π/4)
z2 = (1,2π) = (1,0)
no idea how you can say z1=√5, when you already said is is (1,π/4)
z1*z2 = (1,π/4)
z1+z2 = (1/√2 + 1/√2 i)+(1+0i) = (1+1/√2)+1/√2 i
|z1+z2| = √((1+1/√2)^2 + 1/2) = √(2+√2)
I can't fathom just what the question is, much less the answer...
that is (1,π/4)
z2 = (1,2π) = (1,0)
no idea how you can say z1=√5, when you already said is is (1,π/4)
z1*z2 = (1,π/4)
z1+z2 = (1/√2 + 1/√2 i)+(1+0i) = (1+1/√2)+1/√2 i
|z1+z2| = √((1+1/√2)^2 + 1/2) = √(2+√2)
I can't fathom just what the question is, much less the answer...
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