Asked by paula

If a solution of lead iodide has [I-] = 1.1x10-4 M, what is the lead(II)ion concentration at equilibrium?
Answered by DrBob222
Ksp = (Pb^2+)(I^-)^2
Substitute Ksp and I (I^- = 1.1E-4M) and solve for (Pb^2+)
Answered by Anonymous
5.86*10^-9
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