Ask a New Question

Question

If a solution of lead iodide has [I-] = 1.1x10-4 M, what is the lead(II)ion concentration at equilibrium?
10 years ago

Answers

DrBob222
Ksp = (Pb^2+)(I^-)^2
Substitute Ksp and I (I^- = 1.1E-4M) and solve for (Pb^2+)
10 years ago
Anonymous
5.86*10^-9
9 years ago

Related Questions

what mass of lead (II) iodide (PbI2, mass= 461 amu)is predictated by the addition of an excess of po... what mass of lead (ii) iodide (pbl2, mass=461 amu)is precipitated by the addition of an excess of po... Give the formula of lead iodide showing all working. You must use knowledge about atoms and electron... Lead iodide, PbI2, has a Ksp in water of 7.1e-9 M3 at room temperature. Calculate the solubility... How many moles of lead iodide are produced from 300. g of potassium iodide? Usie the reaction below.... Lead iodide is a relatively insoluble compound. It can dissolve from the solid phase into the aqueou... why is lead 2 iodide produced from the reaction of lead 2 nitrate and potassium iodide? Describe how lead(II) iodide cen be prepared in the laboratory Lead(ll) Iodide can be produced from the reaction of Lead(ll) nitrate and potassium Iodide.What mass... Lead (2) iodide is an insoluble salt What method can be used to prepare it
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use