Asked by Hannah
According to a college survey, 22% of all students work full time. Find the mean and standard deviation for the number of students who work full time in samples of size 16.
Answers
Answered by
kudum
mu = np
mean = np
= 0.22 *16 =3.52
Standard Deviation = Sqrt(n PQ)
= Sqrt(16 *.22 *.78)
= 1.656985
mean = np
= 0.22 *16 =3.52
Standard Deviation = Sqrt(n PQ)
= Sqrt(16 *.22 *.78)
= 1.656985
Answered by
Anonymous
A 27 year old woman decides to pay $156 for a 1 year life insurance policy with coverage of $100,000. The probability of her living through the year is 0.9995. Determine her expected value for the insurance policy show work
Answered by
Eliana
According to a college survey, 22% of all students work full time. Find the mean for the number of students who work full time in samples of size 16.
Answered by
Dyllan
3.52 is the answer to this question
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