(tanx-8)(tanx+1) = 0
tanx = 8 or -1
arctan(8) = 1.446 or 4.588
arctan(-1) = 3π/4 or 7π/4
tan^2 x − 7 tan x − 8 = 0
Use inverse functions where needed to find all solutions of the equation in the interval [0, 2π).
1 answer