Question
In a coffee cup calorimeter, 50 mL of 0.1 M HCl and 50 mL of 0.1 M NaOH are mixed to
yield the following reaction: HCl + NaOH NaCl + H2O. The two solutions were initially at 22.1 oC and the final temperature is 24.2 oC. Calculate the heat that accompanies this reaction in kJ/mol of H2O formed. Assumed the combined solution has a mass of 100 g and a specific heat of 4.18 J/gK
yield the following reaction: HCl + NaOH NaCl + H2O. The two solutions were initially at 22.1 oC and the final temperature is 24.2 oC. Calculate the heat that accompanies this reaction in kJ/mol of H2O formed. Assumed the combined solution has a mass of 100 g and a specific heat of 4.18 J/gK
Answers
How many mols H2O were formed? That's 50 x 0.1 = 5.0 millimols or 0.005 mols.
q = heat released = mass H2O x specific heat H2O x (Tfinal-Tinitial)
That is q for 0.05 mols. Convert to J/1 mol and to kJ/mol.
q = heat released = mass H2O x specific heat H2O x (Tfinal-Tinitial)
That is q for 0.05 mols. Convert to J/1 mol and to kJ/mol.
8.778 KJ/Mole
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