Asked by Anonymous

I have to factor this to find what this graph looks like but I don't know if I'm doing it right.

6x^2-12x+6y^2+36y=36
3x^2-6x+3y^2+18y=18

I'm stopping there because I don't know if I divide by 2 or 6
Answered by bobpursley
In the original equation, all coefficents are multiples of six. Divide by six.
Answered by Anonymous
6x^2-12x+6y^2+36y=36
x^2-2x+y^2+6y=6
(x^2-2x+1)+(y^2+ I'm stuck
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