Asked by LK

demoivre theorem

(2sqrt3+2i)^5

r=(2sqrt3+2)^2
Answered by Steve
r^2 = (2√3)^2 + 2^2 = 16, so r=4
(2√3 + 2i) = (4,π/6)

(2√3 + 2i)^5 = (4^5,5π/6) = (-512√3,512)
Answered by Anonymous
whats (2√3)^2 equal to?
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