f'(x)=sin(x)
then by the derivative of trig functions, f(x)=-cos(x)+C
Now solve for C in
f(π)=-cos(π)+C=3
If f'(x)=sinx and f(pi)=3, then f(x)=
A. Cosx+4
B. Cosx+3
C. -cosx+2
D. -cosx-2
E. -cosx+4
3 answers
-cosx+2
3 + cosx