Asked by John
A 450 kg car traveling north at 30 m/s collides with a 560 kg car traveling west at 35 m/s. If after the collision they become entangled and move off together, (a) what is magnitude of the final momentum of the cars? (b) What is their final speed of the cars? (c) What is their direction relative to the -x axis?
I understand that this specific word problem is an Inelastic equation, and I already have made my chart for object A, and object B. I'm just not sure what to do next.
I understand that this specific word problem is an Inelastic equation, and I already have made my chart for object A, and object B. I'm just not sure what to do next.
Answers
Answered by
Henry
M1*V1 + M2*V2 = M1*V + M2*V
450*30i + 560*(-35) = 450V + 560V
13,500i - 19,600 = 1,010V
b. V = -19.41 + 13.37i
V = sqrt = (19.41^2+13.37^2) = 23.6 m/s.
a. Momentum = M1*V + M2*V =
450*23.6 + 560*23.6 = 23,836 kg-m/s.
c. Tan A = Y/X = 13.71/-19.41=-0.70634
A = -35.2o = 35.2o CW from -x axis =
35.2o N. of W.
450*30i + 560*(-35) = 450V + 560V
13,500i - 19,600 = 1,010V
b. V = -19.41 + 13.37i
V = sqrt = (19.41^2+13.37^2) = 23.6 m/s.
a. Momentum = M1*V + M2*V =
450*23.6 + 560*23.6 = 23,836 kg-m/s.
c. Tan A = Y/X = 13.71/-19.41=-0.70634
A = -35.2o = 35.2o CW from -x axis =
35.2o N. of W.
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