I'm having problems with one of the questions on my homework. It has 4 parts. Thanks
9) y = -2(x + 5)^2 + 4
A) Find Vertex
B) Find the Zeros
C) Find the y-intercept(s)
D) This function has a:
a) Minimum b) Maximum
3 answers
By the way, I think I figured out part A. I have the vertex as -2(-5+5)^2+4=4, so the vertex is (-5, 4). Please confirm, thanks.
surely, giben the vertex form of the parabola, you can read off the vertex?
for the zeros, just solve normally the quadratic
-2(x+5)^2 + 4 = 0
the y-intercept is where x=0
The parabola opens downward, so there is no minimum
The vertex is the maximum, which you have already found.
for the zeros, just solve normally the quadratic
-2(x+5)^2 + 4 = 0
the y-intercept is where x=0
The parabola opens downward, so there is no minimum
The vertex is the maximum, which you have already found.
A) I have the maximum height 47.55 or 47.6
B) I have 5.5 seconds that it will hit the ground
B) I have 5.5 seconds that it will hit the ground
2 answers