Asked by som
4x^4-18x^2=0 solve by factoring
Answers
Answered by
Fredr
0 = 4x^4-18x^2
= 4x^2(x^2-9/2)
= 4x^2(x+sqrt(9/2))(x-sqrt(9/2))
= 4x^2(x^2-9/2)
= 4x^2(x+sqrt(9/2))(x-sqrt(9/2))
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