Asked by kudu
a model of a solid structure in the shape of frustum of a cone with hemispherical top. The diameter of the hemispherical part is 70 cm and is equal to the diameter of the top of the frustum. The frustum has a base diameter of 28 cm and slant height of 60 cm.)
(a) The area of hemispherical surface.
b) The total surface area of the model
(a) The area of hemispherical surface.
b) The total surface area of the model
Answers
Answered by
Steve
2/5 of the height of the cone is missing. The complete cone would have a slant height of 100.
The lateral area of a cone is πrs, so what we have is π(35)(100) - π(14)(40) = 2940π
The hemisphere has area 2πr^2 = 2π(35^2) = 2450π
The bottom of the shape is a circle of radius 14, with area 196π
So, add 'em all up for the total area.
The lateral area of a cone is πrs, so what we have is π(35)(100) - π(14)(40) = 2940π
The hemisphere has area 2πr^2 = 2π(35^2) = 2450π
The bottom of the shape is a circle of radius 14, with area 196π
So, add 'em all up for the total area.
Answered by
lagat
the total surface area of the model
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