Asked by Tokisetso
p^2x - 2q^2y - 2pqx + pqy
Answers
Answered by
Steve
rearrange a bit and you have
px(p-2q) - qy(p-2q)
(px-qy)(p-2q)
px(p-2q) - qy(p-2q)
(px-qy)(p-2q)
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