Asked by mouzam
                what is the mass of the toy truck if the force of friction holding it in place is 18.5N        u= 0.2       at 30 degrees
            
            
        Answers
                    Answered by
            Henry
            
    Fp = Mg*sin30 = 0.5Mg = Force parallel
to the plane.
0.5Mg = 18.5
Mg = 37 N = Wt. of the toy.
M = 37/g = 37/9.8 = 3.8 kg = Mass of toy
    
to the plane.
0.5Mg = 18.5
Mg = 37 N = Wt. of the toy.
M = 37/g = 37/9.8 = 3.8 kg = Mass of toy
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