Asked by mouzam
what is the mass of the toy truck if the force of friction holding it in place is 18.5N u= 0.2 at 30 degrees
Answers
Answered by
Henry
Fp = Mg*sin30 = 0.5Mg = Force parallel
to the plane.
0.5Mg = 18.5
Mg = 37 N = Wt. of the toy.
M = 37/g = 37/9.8 = 3.8 kg = Mass of toy
to the plane.
0.5Mg = 18.5
Mg = 37 N = Wt. of the toy.
M = 37/g = 37/9.8 = 3.8 kg = Mass of toy
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