Asked by Anonymous

Express cube root 27x^4y^6 using rational exponents

(27x^4y^6)1/3
(27^1/3)(x^4/3)(y^6/3)

stuck. I think the final answer is 9x^3/4(y^2) I don't know where to put the parentheses to break it up so I hope yall understand what it's suppose to be.

Answers

Answered by bobpursley
it is wrong. What is the cube root of 27? Hint, it is not 9.

Secondly, the cube root of x^4 is x^(4/3)
Answered by Michael omoloye
By simplify: we get (27)^1/3 * (x^4)^1/3 * (y^6)^1/3 =3y^2x^4/3

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