Asked by Anonymous
Express cube root 27x^4y^6 using rational exponents
(27x^4y^6)1/3
(27^1/3)(x^4/3)(y^6/3)
stuck. I think the final answer is 9x^3/4(y^2) I don't know where to put the parentheses to break it up so I hope yall understand what it's suppose to be.
(27x^4y^6)1/3
(27^1/3)(x^4/3)(y^6/3)
stuck. I think the final answer is 9x^3/4(y^2) I don't know where to put the parentheses to break it up so I hope yall understand what it's suppose to be.
Answers
Answered by
bobpursley
it is wrong. What is the cube root of 27? Hint, it is not 9.
Secondly, the cube root of x^4 is x^(4/3)
Secondly, the cube root of x^4 is x^(4/3)
Answered by
Michael omoloye
By simplify: we get (27)^1/3 * (x^4)^1/3 * (y^6)^1/3 =3y^2x^4/3
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