Question

p^2x - 2q^y - 2 pqx + pqy

Answer 1

Do you mean

(p^2)(x) or p^(2x)
2q^y or 2q^2 y

The mixture of exponents and multiplication seems unlikely. I will assume you meant

p^2 x - 2q^2 y - 2 pqx + pqy
= (p-2q)px + (p-2q)qy
= (p-2q)(px+py)

Answer 2

I ment
(p^2)(x) - (2q^2)(y) -(2pqx) + (pqy)

Answer 3

I ment
(p^2)(x) - (2q^2)(y) -(2pqx) + (pqy)