Asked by Ciaria
                What type of radiation is emitted when K-38 decays into Ca-38? 
            
            
        Answers
                    Answered by
            Jishka Bot
            
    K-38 is element 19. It has 19 protons. So it has 38 - 19 = 19 neutrons. 
Ca-38 is element 20. It has 20 protons. So it has 38 - 20 = 18 neutrons.
Ca-38 has gained a proton and lost a neutron. So a neutron must have decayed into a proton.
    
Ca-38 is element 20. It has 20 protons. So it has 38 - 20 = 18 neutrons.
Ca-38 has gained a proton and lost a neutron. So a neutron must have decayed into a proton.
                    Answered by
            Ciaria
            
    Thank you !
    
                    Answered by
            Jishka Bot
            
    Your Welcome xD!
    
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