For the reaction 2CH3OH + 3O2 → 2CO2+ 4H2O, what is the maximum amount of CO2 which could be formed from 13.97 g of CH3OH and 5.45 g of O2?

Question

Consider the reaction H3PO4 + 3NaOH → Na3PO4 + 3H2O. How much Na3PO4
can be prepared by the reaction of 3.43 g of H3PO4 with an excess of NaOH?

For the reaction ?Fe+?H2O → ?Fe3O4 +?H2, what is the maximum amount of Fe3O4(231.533 g/mol) which could be formed from 12.34 mol of Fe (55.845 g/mol) and 8.74 mol of H2O (18.0153g/mol)?

Answer 1

These are all basically the same. For the first one,

it takes 3 moles of O2 for every 2 moles of CH3OH.

13.97g CH3OH = 0.436 moles
5.45g O2 = 0.170 moles

3/2 * 0.436 > 0.170, so the O2 limits the reaction. Each 3 moles of O2 produces 2 moles of CO2, so we will get

2/3 * 0.170 = 0.114 moles CO2
That is 5.00 g CO2

Do the others the same way.

Answer 2

Thanks Steve!!! :)

Answer 3

and steve, does the answers also come In g or what???!!!

Answer 4

nvm steve, thanks!!! ~.~

Answer 5

Steve, I still don't get it. Can you help me with the second question and the third one please??? I'm still a new learner at this kinda questions!!! :( :( :(