Asked by Shane
A 2.40 kg mess kit sliding on a frictionless surface explodes into two 1.20 kg parts:
3.78 m/s, due north, and 5.28 m/s, 32.8° north of east. What is the original speed of the mess kit?
3.78 m/s, due north, and 5.28 m/s, 32.8° north of east. What is the original speed of the mess kit?
Answers
Answered by
Henry
M1*V1 = M2*V2 + M3*V3
2.4*V1 = 1.2*3.78[90o] + 1.2*5.28[32.8o]
2.4V1 = 4.54i + 4.44 + 5.33 + 3.43i
2.4V1 = 9.77 + 7.97i
V1 = 4.07 + 3.32i
V1 = sqrt(4.07^2+3.32^2) = 5.25 m/s
2.4*V1 = 1.2*3.78[90o] + 1.2*5.28[32.8o]
2.4V1 = 4.54i + 4.44 + 5.33 + 3.43i
2.4V1 = 9.77 + 7.97i
V1 = 4.07 + 3.32i
V1 = sqrt(4.07^2+3.32^2) = 5.25 m/s
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