Asked by Vikki
The question is asking to calculate the overall energy change in the combustion of ethane (C2H6). This is what I have done:
The balanced equation:
C2H6 + 6 O2 --> 2 CO2 + 3 H2O
(6) 411 + 346 + (6) 494 --> (2) 799 + (3) 459
2466 + 346 + 2964 --> 1598 + 1377
= 5776 = 2975
5776 - 2975 = 2801
2801 kJ/mol of ethane / 30.08 g/mol = 93.11
The answer in the text book says 47 kJ/g.
What am I doing wrong?
The balanced equation:
C2H6 + 6 O2 --> 2 CO2 + 3 H2O
(6) 411 + 346 + (6) 494 --> (2) 799 + (3) 459
2466 + 346 + 2964 --> 1598 + 1377
= 5776 = 2975
5776 - 2975 = 2801
2801 kJ/mol of ethane / 30.08 g/mol = 93.11
The answer in the text book says 47 kJ/g.
What am I doing wrong?
Answers
Answered by
Anonymous
you didn't balance the equation properly
it's supposed to be
2C2H6 + 702 -> 4CO2 + 6H2O
it's supposed to be
2C2H6 + 702 -> 4CO2 + 6H2O
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.