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A plastic rod is rubbed against a wool shirt, thereby acquiring a charge of −4.9 µC. How many electrons are transferred from th...Asked by Bob
A plastic rod is rubbed against a wool shirt,
thereby acquiring a charge of −4.9 µC.
How many electrons are transferred from
the wool shirt to the plastic rod? The elemental
charge is 1.6 × 10−19 C.
thereby acquiring a charge of −4.9 µC.
How many electrons are transferred from
the wool shirt to the plastic rod? The elemental
charge is 1.6 × 10−19 C.
Answers
Answered by
Tia
A plastic rod is rubbed against a wool shirt, thereby acquiring a charge of -1 µC.Thus there will transfer of electron take place. So problem is to find how many electrons will transfer from the wool shirt to the plastic rod?
Since we know 1C charge acquired when 1.6x10^19 electrons transferred.
Since
1C=10^6 mu C
Thus
10^6 mu C acquired when 1.6x10^19 electrons transferred.
1 mu C acquired when (1.6x10^19)/10^6 electrons transferred which equal to
=1.6x10^(19-6)
=1.6x10^13
Thus in acquiring -1 mu C charge there will 1.6x10^13 electrons will transfer from wool shirt to plastic rod.
Since we know 1C charge acquired when 1.6x10^19 electrons transferred.
Since
1C=10^6 mu C
Thus
10^6 mu C acquired when 1.6x10^19 electrons transferred.
1 mu C acquired when (1.6x10^19)/10^6 electrons transferred which equal to
=1.6x10^(19-6)
=1.6x10^13
Thus in acquiring -1 mu C charge there will 1.6x10^13 electrons will transfer from wool shirt to plastic rod.
Answered by
Bob
incorrect
Answered by
Damon
-19+6 = -13
so
1.6 * 10^-13 uC /electron
so
(1/1.6)*10^13 electrons/uC
= .625 * 10^13
= 6.25 * 10^12 electrons
so
1.6 * 10^-13 uC /electron
so
(1/1.6)*10^13 electrons/uC
= .625 * 10^13
= 6.25 * 10^12 electrons
Answered by
chzrli
3.0625E13
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