Asked by rajeev
A bullet is fired with an initial velocity 300m s at an angle 30 degree with horizontal . At what distance from the gun will the bullet strike the ground ?
Answers
Answered by
Henry
d = Vo^2*sin(2A)/g = 300^2*sin(60)/9.8 =
Answered by
someone
R=u^2sin2(A)/g
R=150^2*3*sin60/9.8
R=150^2*3*sin60/9.8
Answered by
Osvaldo Silguero
175m/s
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