Asked by Darren

What is the (OH-) when pH = 4.25
Answered by DrBob222
Remember this.
pH + pOH = pKw = 14
You know pKw and pH, solve for pOH. Then
pOH = -log(OH^-), substitute and solve for OH^-.
Answered by Darren
im confused, is the answer 1.77827941x10^-10 or 5623413252????
Answered by DrBob222
It's 1.78E-10.
Why are you confused.
14-4.25 = 9.75 = pOH
Then pH = -log(OH^-)
-9.75 = log OH^-
OH^- = 1.78E-10

OR

OH^- = 10^-pOH
OH^- = 1.78E-10
There are no AI answers yet. The ability to request AI answers is coming soon!