Asked by Ann
I have no idea where to start with this one...
Calculate the concentration (M) of sodium ions in a solution made by diluting 40.0ml of a 0.474m solution of sodium sulfide to a total volume of 300ml
Calculate the concentration (M) of sodium ions in a solution made by diluting 40.0ml of a 0.474m solution of sodium sulfide to a total volume of 300ml
Answers
Answered by
DrBob222
Is this 0.474m or 0.474M? I assume you know there is a difference between the two.
Answered by
DrBob222
M make it easier to do.
Start M Na2S = 0.474
New M Na2S after dilution = 0.474 x (40 mL/300 mL) = ?M Na2S
Since there are 2 Na ions for each molecule of Na2S, then (Na^+) will be just twice that of Na2S.
Start M Na2S = 0.474
New M Na2S after dilution = 0.474 x (40 mL/300 mL) = ?M Na2S
Since there are 2 Na ions for each molecule of Na2S, then (Na^+) will be just twice that of Na2S.
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