A). M = mols/L. You took g/L.
Convert 3.60 g H2SO4 to mols. mol = grams/molar mass; then mols/L solution.
B)
I believe you are over thinking these problems. Just remember the definition. molarity = M = mols/L You have mols in B already. You have volume in mL, convert to L, then substitute into mols/L = M.
I need to figure out the molarity in the problem.
A) 3.60g of sulfuric acid in 450.0mL of solution
I was going to take 3.60 / 450.0mL = 0.008
B) 2.0 x 10-3 mol Iron(II)nitrate in 12.0mL of Solution
10 *3=30 then I was going to take 30*2.0 =60
60/12.0= 5
I am not sure if this is correct.
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