Experiment 1 results:

Question

mass of crucible 88g
mass of hydrate 93g
mass of salt 91.196g

1. Calculate the following:
a:mass of water in the hydrate sample (g)
b:number of moles of water in the sample
c:mass of pure salt in the sample (g)
d:number of moles of salt in the sample
e:molar ratio of water to salt in the sample
2. From your calculations, what is the empirical formula of copper sulfate hydrate?
3.4. Write the equation for the decomposition of the hydrate, CuSO4*XH2O.

Experiment 2 results:
mass of crucible: 88g
mass of hydrate and crucible: 93g
mass of salt:90.342

1. Calculate the following:
a:mass of water in the hydrate sample (g)
b:number of moles of water in the sample
c:mass of pure salt in the sample (g)
d:number of moles of salt in the sample
e:molar ratio of water to salt in the sample

2.From your calculations, what is the empirical formula of magnesium chloride hydrate?

3.Write the equation for the decomposition of the hydrate, MgCl2*XH2O.

Answer 1

These are the calculations I can up with for experiment 1:

a:mass of water in the hydrate sample (g) 1.804g
b:number of moles of water in the sample 0.100g
c:mass of pure salt in the sample (g) 3.196g
d:number of moles of salt in the sample .0214g
e:molar ratio of water to salt in the sample 4.673g

For Experiment 2:
a:mass of water in the hydrate sample (g) 2.658g
b:number of moles of water in the sample 0.148g
c:mass of pure salt in the sample (g) 2.342g
d:number of moles of salt in the sample 0.016g
e:molar ratio of water to salt in the sample 9.25g

I really just need it checked and help with the formulas please!

Answer 2

Formulas for experiment 1:
CuSO4*5H2O
CuSO4.XH2O --------> CuSO4 + XH2O

Formulas for experiment 2:
MgCl2·6H2O
MgCl2 * X H2O = MgCl2 + X H2O

I just need someone to check my answers please :)