Asked by qwerty

Let A,B,C be three events and let X=IA, Y=IB, Z=IC be the associated indicator random variables. We already know that X⋅Y is the indicator random variable of the event A∩B. In the same spirit, give an algebraic expression, involving X, Y, Z for the indicator random variable of the following events.

The event Ac∩Cc

Exactly one of the events A, B, C occurred.

Answers

Answered by RVE
1. (1-X)*(1-Z)

be aware your keyboard is set to US language not US international or other language
Answered by Milorad
2) X*(1-X*Y)*(1-X*Z) + Y*(1-X*Y)*(1-Y*Z) + Z*(1-X*Z)*(1-Y*Z)
Answered by 123
2) Exactly one of the events A, B , C occurs:
[A ∩ (Bc ∩ Cc)] ∪ [B ∩ (Cc ∩ Ac)] ∪ [C ∩ (Ac ∩ Bc)]

Using 1) Indicator for the first formula: X*(1-Y)*(1-Z)
Now we have to use De Morgan Law and finally we have:

1-(1-X*(1-Y)*(1-Z))*(1-(1-X)*Y*(1-Z))*(1-(1-X)*(1-Y)*Z)
Answered by RVE
2. official answer:

1-(1-(X)*(1-Y)*(1-Z))*(1-(1-X)*(Y)*(1-Z))*(1-(1-X)*(1-Y)*(Z))
Answered by P
and if at most two of the events A, B, C occurred?
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