Asked by meri
write an equation for the line that passes though (3,3) and is parallel to the line with equation 4x+y-5=0
Answers
Answered by
Steve
4x+y-5=0 has slope -4
So, now you have a point and a slope:
y-3 = -4(x-3)
So, now you have a point and a slope:
y-3 = -4(x-3)
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