Question

A package is dropped from a helicopter flying at a height of 7.5 m while traveling 15 m/s. How far is the package travel horizontally before it hits the ground below?

Answer 1

h = 0.5g*t^2 = 7.5
4.9t^2 = 7.5
t^2 = 1.53
t = 1.24 s. = Fall time.

d = Vx*t = 15m/s * 1.24s = 18.6 m.

Answer 2

h = 0.5g*t^2 = 7.5
4.9t^2 = 7.5
t^2 = 1.53
t = 1.24 s. = Fall time.

d = Vx*t = 15m/s * 1.24s = 18.6 m.

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