Asked by Hababa
A gardener holds a hose 0.75 m above the ground such that water shoots out horizontally and hits the ground at a point 2 m away. What is the speed with which the water leaves the hose?
Answers
Answered by
Anonymous
123.56
Answered by
To anonymous
Solution please?
Answered by
Steve
how long does it take to fall 0.75m?
4.9t^2 = 0.75
the speed is 2/t m/s
I don't think the above answer is correct.
4.9t^2 = 0.75
the speed is 2/t m/s
I don't think the above answer is correct.
Answered by
Hababa
I calculated it as 5.11 m/s is that right?
Answered by
edk
given
dy= -0.75m
dx= 2m
g= 9.8 m/s²
sol
vx
formula dx=vxt
dx/t=vxt/t
vx=dx/t
solve for t
form; square root of 2dy/g
t= square root of 2(-0.75m)/-9.8m/s²
t=0.39s
vx= dx/t
v= 2m/39
answer= 5.13 m/s
dy= -0.75m
dx= 2m
g= 9.8 m/s²
sol
vx
formula dx=vxt
dx/t=vxt/t
vx=dx/t
solve for t
form; square root of 2dy/g
t= square root of 2(-0.75m)/-9.8m/s²
t=0.39s
vx= dx/t
v= 2m/39
answer= 5.13 m/s
Answered by
bobo
pakyu
Answered by
Anonymous
suck
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