What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y equals= 12 minus x^2?

Answer 1

If the rectangle has width 2x, then the area is

a = 2xy = 2x(12-x^2)
da/dx = 24 - 6x^2 = 6(4-x^2)
da/dx=0 when x=2
So, the largest area is 4(12-2^2) = 32

Answer 2

bro this has to be a joke. Half of the responses are like, Answer = Doing the right steps to find the answer.