Asked by Oscar
Someone please help
2. You toss a coin 15 times. P(heads) 2/5 =
• experimental; the result is found by repeating an experiment. ****
• experimental; the result is based on the number of possible outcomes.
• theoretical; the result is found by repeating
theoretical; the result is based on the number of possible outcomes
I think its A. Someone please help me. Ms Sue
2. You toss a coin 15 times. P(heads) 2/5 =
• experimental; the result is found by repeating an experiment. ****
• experimental; the result is based on the number of possible outcomes.
• theoretical; the result is found by repeating
theoretical; the result is based on the number of possible outcomes
I think its A. Someone please help me. Ms Sue
Answers
Answered by
Ms. Sue
I believe you're right.
Answered by
Oscar
Thank you Could you help me with a couple more
Answered by
Ms. Sue
I'll try to help you -- but this is not my field.
Answered by
Michigan Connexus
Yeah you’re right
Answered by
Minecraft player
...2,753 people have been here and no one has the answer. >:( This sucks.
Answered by
bot help
you toss a coin 15 times. p(heads) 2/5=
bot please help
bot please help
Answered by
Bot
The answer is theoretical; the result is based on the number of possible outcomes. When you toss a coin, there are two possible outcomes - heads or tails. The probability of getting heads on a single toss is 1/2 or 0.5. Therefore, the probability of getting heads on 15 tosses can be calculated using the binomial probability distribution formula:
P(X = k) = nCk * p^k * (1-p)^(n-k)
Where:
n = 15 (number of trials)
k = number of successes (getting heads)
p = probability of getting heads (2/5 = 0.4)
P(X = 7) = 15C7 * 0.4^7 * (1-0.4)^(15-7)
P(X = 7) = 0.174
Therefore, the probability of getting exactly 7 heads in 15 tosses of a coin with a probability of 2/5 (0.4) of getting heads on a single toss is 0.174 or approximately 17.4%.
P(X = k) = nCk * p^k * (1-p)^(n-k)
Where:
n = 15 (number of trials)
k = number of successes (getting heads)
p = probability of getting heads (2/5 = 0.4)
P(X = 7) = 15C7 * 0.4^7 * (1-0.4)^(15-7)
P(X = 7) = 0.174
Therefore, the probability of getting exactly 7 heads in 15 tosses of a coin with a probability of 2/5 (0.4) of getting heads on a single toss is 0.174 or approximately 17.4%.
Answered by
lol
thanks bot
Answered by
Bot
You're welcome! Let me know if you have any more questions.
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