Asked by Jennie
Ok, UMMMM I thought I was good.. Till now..
Ok, For Cup C
Mass of cup,water,stirrer: 55.15
Mass of sodium bicarbonate: 2.02g
mass of citric acid: 0.77g
total mass: 57.94g
mass of cup,solution, stirrer after reaction: 57.64
difference (CO2): 0.30g
Part B: Limiting Reactants
Plastic Cup C
7. Determine which reactant is the limiting reactant in the plastic cup C. Describe your reasoning.
You know I know how to calculate the TY and AY and %Y now, but I'm confused on the finding limiting reactant? umm Let me see if I can figure it out and you let me know if I'm on the right track...
2.02g NaHCO3 mols = 2.02/84 = 0.0240 mols
the ratio is 3/1 for NaHCO3toH3C6H5O7 so do I do 0.0240/3 = citric acid? 0.008 moles citric acid? so since citric acid is smaller but it requires 3 of sodium bicarbonate, would that be the limiting reactant? because it takes more of them? am I figuring this out right?
8. Calculate the theoretical yield of carbon dioxide in the plastic cup C.
2.02/84=0.0240 *44 = 1.056 TY??
9. Calculate the percentage yield in the plastic cup C.
AY = 0.30/1.056 TY = 0.284*100 = 28.4% ?? is this right?
Ok, For Cup C
Mass of cup,water,stirrer: 55.15
Mass of sodium bicarbonate: 2.02g
mass of citric acid: 0.77g
total mass: 57.94g
mass of cup,solution, stirrer after reaction: 57.64
difference (CO2): 0.30g
Part B: Limiting Reactants
Plastic Cup C
7. Determine which reactant is the limiting reactant in the plastic cup C. Describe your reasoning.
You know I know how to calculate the TY and AY and %Y now, but I'm confused on the finding limiting reactant? umm Let me see if I can figure it out and you let me know if I'm on the right track...
2.02g NaHCO3 mols = 2.02/84 = 0.0240 mols
the ratio is 3/1 for NaHCO3toH3C6H5O7 so do I do 0.0240/3 = citric acid? 0.008 moles citric acid? so since citric acid is smaller but it requires 3 of sodium bicarbonate, would that be the limiting reactant? because it takes more of them? am I figuring this out right?
8. Calculate the theoretical yield of carbon dioxide in the plastic cup C.
2.02/84=0.0240 *44 = 1.056 TY??
9. Calculate the percentage yield in the plastic cup C.
AY = 0.30/1.056 TY = 0.284*100 = 28.4% ?? is this right?
Answers
Answered by
DrBob222
You know I know how to calculate the TY and AY and %Y now, but I'm confused on the finding limiting reactant? umm Let me see if I can figure it out and you let me know if I'm on the right track...
2.02g NaHCO3 mols = 2.02/84 = 0.0240 mols
the ratio is 3/1 for NaHCO3toH3C6H5O7 so do I do 0.0240/3 = citric acid? 0.008 moles citric acid? so since citric acid is smaller but it requires 3 of sodium bicarbonate, would that be the limiting reactant? because it takes more of them? am I figuring this out right?
<b>I can't tell which you're calling the LR. Citric acid is the LR. Based on you 2.02 g it requires 0.008 mols citric acid and you have only 0.004 so you don't have enough citric acid and that makes it the LR.</b>
8. Calculate the theoretical yield of carbon dioxide in the plastic cup C.
2.02/84=0.0240 *44 = 1.056 TY??
<b>If citric acid is the LR then you should use it to determine the theoretical yield. This calls into question some of the earlier answers since I didn't check them for the LR bit. But it stands to reason that if 1 g NaHCO3 is equivalent to 0.76 g citric acid then if you start with 2.02 g NaHCO3 it will take more than 0.76 g citric acid and there isn't enough there to do anything except with 1g NaHCO3. </b>
9. Calculate the percentage yield in the plastic cup C.
AY = 0.30/1.056 TY = 0.284*100 = 28.4% ?? is this right?
<b>TY needs to be recalculated.</b>
2.02g NaHCO3 mols = 2.02/84 = 0.0240 mols
the ratio is 3/1 for NaHCO3toH3C6H5O7 so do I do 0.0240/3 = citric acid? 0.008 moles citric acid? so since citric acid is smaller but it requires 3 of sodium bicarbonate, would that be the limiting reactant? because it takes more of them? am I figuring this out right?
<b>I can't tell which you're calling the LR. Citric acid is the LR. Based on you 2.02 g it requires 0.008 mols citric acid and you have only 0.004 so you don't have enough citric acid and that makes it the LR.</b>
8. Calculate the theoretical yield of carbon dioxide in the plastic cup C.
2.02/84=0.0240 *44 = 1.056 TY??
<b>If citric acid is the LR then you should use it to determine the theoretical yield. This calls into question some of the earlier answers since I didn't check them for the LR bit. But it stands to reason that if 1 g NaHCO3 is equivalent to 0.76 g citric acid then if you start with 2.02 g NaHCO3 it will take more than 0.76 g citric acid and there isn't enough there to do anything except with 1g NaHCO3. </b>
9. Calculate the percentage yield in the plastic cup C.
AY = 0.30/1.056 TY = 0.284*100 = 28.4% ?? is this right?
<b>TY needs to be recalculated.</b>