Asked by Kyle
Emma's school plans to build a rectangular basketball court with an area of 150+175t square feet. The length of the basketball court is 25 feet as shown in the following diagram.
Thank you!
Thank you!
Answers
Answered by
bobpursley
And the question is?
Answered by
Kyle
SORRY.. here is the question...
What is the width of the basketball court?
What is the width of the basketball court?
Answered by
bobpursley
I am not certain what you mean by an area of 150+175t.
25*W=area
solve for W.
25*W=area
solve for W.
Answered by
Kaleb
The answer should be 175 * 25 + 150
Answered by
Jack
First of all, lets note what the formula is.
A=bh or lw
25 is the width so lets plug it in.
25w=150+175t
Next, you evaluate that by Isolating the "w". Divide the 25 by 25 and divide 150+175t to get 6+7t
Get rekt noob........
A=bh or lw
25 is the width so lets plug it in.
25w=150+175t
Next, you evaluate that by Isolating the "w". Divide the 25 by 25 and divide 150+175t to get 6+7t
Get rekt noob........
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