Do you have a K. I usually use them as g/g and if your prof does the same, then Ko/a = K(16.9/9.5) = 1.78
Then K = (concn organic phase/concn aqueous phase). Let x = g in organic phase, then 5-x = g in aqueous phase.
For org phase you have x/100
For aqueous phase you have (5-x)/150
Solve for x and 5-x
You have a solution that contains 5.0 g of oxalic acid dissolved in 150 mL of water. This solution is placed in a separatory funnel, and then 100 mL of diethyl either is added to the separatory funnel and an extraction is performed (diethyl ether and water are immiscible). Use the following constants to calculate how much oxalic acid is in each solvent after the extraction: solubility of acid in water= 9.5g/100mL and solubility of acid in ether= 16.9 g/100mL
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