Asked by Francis
The line x 7y=5 cuts the circle x^2 y^2=15 at the points P & Q. Find: a) P & Q. b) the midpoint of PQ.
Answers
Answered by
Bosnian
What mean x 7 y = 5 ?
x - 7 y = 5
x + 7 y = 5
x ^ 7 y = 5
x - 7 y = 5
x + 7 y = 5
x ^ 7 y = 5
Answered by
Francis
there's a plus sign in btw x & 7y, d system prolly removed it.
x plus 7y=5
x^2 plus y^2=15
x plus 7y=5
x^2 plus y^2=15
Answered by
MathMate
Put x=5-7y
Substitute in the circle
(5-7y)²+y²=15
Solve for the two values of y.
Find corresponding values of x to give two ordered pairs which are solutions to (a) for P and Q.
For (b), use the mid-point formula
M=((x1+x2)/2, (y1+y2)/2)
If you need further help, please post where you're up to and where you're stuck. You're welcome to post your answers for checking.
Substitute in the circle
(5-7y)²+y²=15
Solve for the two values of y.
Find corresponding values of x to give two ordered pairs which are solutions to (a) for P and Q.
For (b), use the mid-point formula
M=((x1+x2)/2, (y1+y2)/2)
If you need further help, please post where you're up to and where you're stuck. You're welcome to post your answers for checking.
Answered by
david
To solve for the two values of y
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