Question
When adding the square root of 16 and -8 which type of number is the sum?
A. Integer
B. Irrational number
C. Radical
D. Whole number
A. Integer
B. Irrational number
C. Radical
D. Whole number
Answers
MathMate
I interpret
"adding the square root of 16 and -8"
as
"adding the square root of 16 and the square root of -8"
which gives
sqrt(16)+sqrt(-8)
= 4+2√2 i
which is a complex irrational number.
If I interpret
"adding the square root of 16 and -8"
as
"the square root of the sum of 16 and -8", then
the result is
√(16-8)=√8=2√2
which is an irrational number.
You may be in a better position to judge what your teacher means.
"adding the square root of 16 and -8"
as
"adding the square root of 16 and the square root of -8"
which gives
sqrt(16)+sqrt(-8)
= 4+2√2 i
which is a complex irrational number.
If I interpret
"adding the square root of 16 and -8"
as
"the square root of the sum of 16 and -8", then
the result is
√(16-8)=√8=2√2
which is an irrational number.
You may be in a better position to judge what your teacher means.
Jo Mersa Marley
Is this right
Sassquach
Can someone please help me with the rest of the anwsers send them to me on Instagram @jacob_is_santa_24
MathMate why
square root of 16 and adding it to negative 8 makes -4
It would count as a integer
It would count as a integer