Asked by Mahnoor
The rate constant for the decomposition of gaseous azomethane,
C2 H6 N2 (g) > N2 (g) + C2 H6 (g)
Is 40.8 min-1 at 425OC. Find the number of moles azomethane and the number of moles of nitrogen 0.0500 minutes after 2.00 g of azomethane is introduced. Assume that the decomposition reaction is first order and that the reverse reaction can be ignored (Note that the first order integrated rate equation can be expressed in terms of the number of moles of the reacting species instead of the concentration).
Do we use the integrated law here?
C2 H6 N2 (g) > N2 (g) + C2 H6 (g)
Is 40.8 min-1 at 425OC. Find the number of moles azomethane and the number of moles of nitrogen 0.0500 minutes after 2.00 g of azomethane is introduced. Assume that the decomposition reaction is first order and that the reverse reaction can be ignored (Note that the first order integrated rate equation can be expressed in terms of the number of moles of the reacting species instead of the concentration).
Do we use the integrated law here?
Answers
Answered by
DrBob222
Yes, and I would convert 2.00 g azomethane to mols first.
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